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Ant Compile Error In Opening Zip File


Why can't maven handle that? kumar hai Greenhorn Posts: 26 posted 6 years ago Hi, thanks for you reply....my issue resolved .... Starting with ant 1.6, ant will open the files in the classpath checking for manifest entries. keyword2 keyword1 -keyword2 Questions with a specific tag and keyword(s) +[tag1] keyword1 Questions with two or more specific tags and keyword(s) +[tag1] +[tag2] keyword1 To search for all posts by a http://svbuckeye.com/error-in/ant-error-in-opening-zip-file.php

I believe you can adjust the method to suit your needs as all zip classes have equivalent subclasses for .jar archives. The original one was a corrupt jar file and the user solved that. [OCA 8 book] [OCP 8 book] [Blog] [JavaRanch FAQ] [How To Ask Questions The Smart Way] [Book Promos] Also, please note that this exception is seen only on WebSphere and higher versions. Chris Jenkins (1465) OliverRodriguez (7) Mar 19, 2015 at 11:29 AM 0 I'm not sure. More about the author

Error In Opening Zip File Java

Cheers" share|improve this answer answered Sep 1 '11 at 13:59 Alastair Brayne 4461620 I had loads of hidden jars (.!79974!google-play-services.jar) causing the issue, thanks for the idea! –rob5408 Feb What's the difference between a Task List and a Custom List? Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).

Which is faster? I was able to determine that the "corrupted" jar file(s) had a behavior different than "non-corrupted" jar files. A quick solution thats works for me, is: Go to your local repository (in general /.m2/) in your case I see that is C:\Users\suresh.m2) Search for the packages that makes conflicts Error In Opening Zip File Maven Join them; it only takes a minute: Sign up Ant build classpath jar generates “error in opening zip file” up vote 5 down vote favorite 1 I have a project built

Dennis number 2.0 How to deal with a DM who controls us with powerful NPCs? Javac Error In Opening Zip File A colleague's note Ways to tell a person to be quiet Is my workplace warning for texting my boss's private phone at night justified? share|improve this answer edited Nov 28 '08 at 7:48 answered Nov 28 '08 at 7:16 VonC 623k18917811870 Thanks a lot for your response. http://stackoverflow.com/questions/7600028/maven-error-in-opening-zip-file-when-running-maven Did you use the same one and just re-add it or did you find another?

I downloaded a different jar, but the same version. Error In Opening Zip File Eclipse Must have screwed up a download or something at some point. Password Validation in Python Plane determined by two lines What is this syntax inside a GNU C statement expression extension? share|improve this answer answered May 19 '14 at 6:51 user3413464 211 add a comment| up vote 0 down vote This error can occur when your connection gets interrupted during your dependencies

Javac Error In Opening Zip File

Let's start with the what the error message says. I can manually workaround this issue by: for each corrupt jar file - rename to .zip and extract to create a new jar (this turns a corrupt jar into a non-corrupt Error In Opening Zip File Java Total time: 0 seconds below i mention my scripts here only i got error...please help .... Error In Opening Zip File Jenkins Anonymous Sign in Create Ask a question Spaces API Connect Appsecdev BPM Blockchain Bluemix CICS Cloud Analytics Cloud marketplace Content Services (ECM) Continuous Testing Courses DB2 LUW DataPower Decision Optimization DevOps

Finding File name οf currently open file in vi on terminal more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info click site Any help would be greatly appreciated. If it's corrupted or not able to unzip, this error will occur. You may want to check what settings XML to see if you're set to a different repository, such as a local nexus server. Error In Opening Zip File Gradle

share|improve this answer answered Nov 28 '08 at 17:50 Artur... 784 add a comment| up vote 2 down vote I solved this by clearing the jboss-x.y.z/server[config]/tmp and jboss-x.y.z/server/[config]/work directories. That worked for me. –shashaDenovo Dec 13 '14 at 10:15 1 Worked good for me too... Also, when I use JarInputStream instead of JarFile, I am able to read the contents of the Jar file without any exceptions. news asked 6 years ago viewed 13711 times active 4 years ago Get the weekly newsletter!

I've also tried from the commandline and as sudo - again, same results. Java.util.zip.zipexception Error In Opening Zip File Linux Try JIRA - bug tracking software for your team. Can you open it in a WinZip or other compression tool? –VonC Apr 8 '10 at 16:14 Sigh.

I found a 302.

Although this works, it is a painful resolution to an automated build =) I am looking for some guidance as to what may have caused this and how to troubleshoot the Is there any way to make the cut command read the last field only? Usage of "it" to start a sentence Ways to tell a person to be quiet What is this syntax inside a GNU C statement expression extension? Error In Opening Zip File Weblogic Show Hide Answers Answers & comments Related questions How can I migrate Work Items from CS/Next to IBM dev OPS? 1 Answer Error while uploading exisiting large project in Jazz Hub

Maven has pulled down some html content describing an error and saved it to a jar file. –Shellum Jul 7 '15 at 15:41 add a comment| up vote 27 down vote Trick is in using ZipInputStream instead of ZipFile and in sequential reading of zip archive. mvn clean install -X > d:\log.txt And in the log file you find messages like these: Downloading: https://repository.apache.org/content/groups/public/org/apache/axis2/mex/1.6.1-wso2v2/mex-1.6.1-wso2v2-impl.jar [DEBUG] Writing resolution tracking file D:\wso2_local_repository\org\apache\axis2\mex\1.6.1-wso2v2\mex-1.6.1-wso2v2-impl.jar.lastUpdated Downloading: http://maven.wso2.org/nexus/content/groups/wso2-public/org/apache/axis2/mex/1.6.1-wso2v2/mex-1.6.1-wso2v2-impl.jar You see, Maven switched repository.apache.org http://svbuckeye.com/error-in/ant-javac-error-in-opening-zip-file.php You could in the manifest of your main jar, refer to the other jars with this attribute: Class-Path: one.jar two.jar three.jar Then, place all of your jars in the same folder.

I had a problem with asm-3.1 (as mentioned in the blog post linked by Takahiko. Tags Spaces API Connect Appsecdev BPM Blockchain Bluemix CICS Cloud Analytics Cloud marketplace Content Services (ECM) Continuous Testing Courses DB2 LUW DataPower Decision Optimization DevOps Services Digital Experience Hadoop IBM Design Again, it required manually getting the file myself. It is possible you were trying to import the zip which caused issues.

Can an opponent folding make you go from probable winner to probable loser? It then still failed on the asm-parent, which was a POM file containing the HTML with a 301. maven share|improve this question edited May 3 at 11:30 R O M A N I A 12k116575 asked Sep 29 '11 at 15:53 UnKnown 5,67141147242 try: mvn -U clean Unsupported IClasspathEntry kind=4?1Maven Error spring-data-neo4j-rest-2.1.0.BUILD-SNAPSHOT.jar; cannot read zip file maven error3Maven project with PI4J library - error in opening zip file0Maven error message regarding missing package or class0Error opening zip file

That jar was corrupt. Must have screwed up a download or something at some point. I was able to get a successful build eventually. So you can either give it more space, clean up log files, etc.

This might prove to be a useful question for someone, but at the moment it shows as 'unanswered'. –martin clayton Jun 24 '11 at 12:18 add a comment| 2 Answers 2 mvn clean install share|improve this answer answered Jan 19 '15 at 4:55 Anuruddha lanka Liyanarachchi 318215 add a comment| up vote -1 down vote Accidently I found a simple workaroud to Why? When the proper way to get the new one fails, manually grab it yourself.

public void unzipFileIntoDirectory(File archive, File destinationDir) throws Exception { final int BUFFER_SIZE = 1024; BufferedOutputStream dest = null; FileInputStream fis = new FileInputStream(archive); ZipInputStream zis = new ZipInputStream(new BufferedInputStream(fis)); ZipEntry entry; more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed share|improve this answer answered Jun 30 '11 at 14:58 bakoyaro 1,83332147 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign it works now.